Tuesday, 8 July 2014
River and Boat problem
How to solve problems of river and boat
Main case
1. To cross the river with the shortest possible path.
2. To cross the river with the minimum possible time.
General info:
Vb = velocity of boat in still water or (actual maximum possible velocity of boat)
Vr = velocity of river w.r.t ground
basic formula "SPEED = DISTANCE /TIME"
CASE 1 "To cross the river with the shortest possible path."
why at an angle ?????
If you wish to cross a river and arrive at a dock that is directly across from you, but the river's current will tend to carry you downstream . Means to remove the effect of rivers flow ,speed or compensate that , you must steer the boat at an angle.
Example :
say
Vr = 4 m/s
V = Vb =5m/s
width of river = 100 m
then using above equations
Vcos(a) = Vr => 5*cos(a) = 4 m/s
=> cos(a) = 4/5
=> (a) = 37 degree
so, Vsin(a) = 5*sin(37) = 5 * (3/5) m/s= 3m/s
T = time taken to cross river = distance/time = w/Vsin(37) = 100/3= 33.33 seconds
required answer = 33.33 secconds.........................................(A)
If you wish to cross a river and arrive at a dock that is directly across from you, but the river's current will tend to carry you downstream . Means to remove the effect of rivers flow ,speed or compensate that , you must steer the boat at an angle.
Example :
say
Vr = 4 m/s
V = Vb =5m/s
width of river = 100 m
then using above equations
Vcos(a) = Vr => 5*cos(a) = 4 m/s
=> cos(a) = 4/5
=> (a) = 37 degree
so, Vsin(a) = 5*sin(37) = 5 * (3/5) m/s= 3m/s
required answer = 33.33 secconds.........................................(A)
2. To cross the river with the minimum possible time.
time taken , Tmin = W/ Vb
Drift (due to current velocity) = Tmin*Vr
- To move with shortest time boat has to keep maximum of its Velocity in vertically direction, i .e Vb .
- The river will still keep pushing boat toward its current direction and will shift its position from A to B.
- Here this shifting is named as drift .
- To move with shortest time boat has to keep maximum of its Velocity in vertically direction, i .e Vb .
- The river will still keep pushing boat toward its current direction and will shift its position from A to B.
- Here this shifting is named as drift .
Example :
say
Vr = 4 m/s
V = Vb =5m/s
width of river = 100 m
then using above equations to cross the river with minimum possible time
T min = W/Vb = 100/5 = 20 seconds
drift = Vr*Tmin = 4*20= 100 m
Example :
say
Vr = 4 m/s
V = Vb =5m/s
width of river = 100 m
then using above equations to cross the river with minimum possible time
T min = W/Vb = 100/5 = 20 seconds
drift = Vr*Tmin = 4*20= 100 m
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